What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case?
1012
1022
1122
1222
Desired number = (Least multiple of four digit of LCM of 3, 4 and 5) + 2 So the LCM of 3, 4, 5 and 6 is 60. The least 4-digit number divisible by 60 is 1020. So with remainder 2 it will be 1020 + 2 = 1022. Answer is (b).
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