Using 2, 2, 3, 3, 3 as digits, how many distinct numbers greater than 30000 can be formed?
3
6
9
12
For the number to be greater than 30000, it must start with the digit 3. Also, as only 5 digits are given to us, all must be used. 3 _ _ _ _ The 4 blanks have to be filled by two 2’s and two 3’s. Number of ways to do so = 4!/(2! 2!) = 6 These numbers are: 33322, 33232, 33223, 32332, 32323, and 32233.
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