There are 24 equally spaced points lying on the circumference of a circle. What is the maximum number of equilateral triangles that can be drawn by taking sets of three points as the vertices?
4
6
8
12
According to a property of circles, angle subtended at centre is double than that at the circumference. So, we need 60° (for condition of equilateral triangles) So, we need 120° at centre. According to symmetry, we can get 24/[(360)/120] = 8 equilateral triangles.
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