For what value of it, the sum of digits in the number (10n + 1) is 2?
For n= 0 only
For any whole number n
For any positive integer n only
For any read number n
(10n + 1) will have sum of digits 2 for any whole number n. Whole numbers are integers starting with 0. Just put different value of n and observe yourself. For n = 0, 100 + 1 = 1 + 1. So sum is 2. For n = 1, 101 + 1 = 11. So sum is 1 + 1 = 2. For n = 2, 102 + 1 = 100 + 1 = 101. So sum is 1 + 1 = 2. So the correct option is (b).
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